Question

Determine algebraically whether the function is even, odd or neither.

f(x)=x^1/3

Answer 1

definitely odd

Answer 2

since
\[f(-3)=\sqrt[3]{-x}=-\sqrt[3]{x}=-f(x)\] for example
\[f(-8)=\sqrt[3]{-8}=-2=-\sqrt[3]{8}\]