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Mathematics 21 Online
OpenStudy (anonymous):

What is the m∠ADC? A)57.5 B)65 C)90 D)115

OpenStudy (anonymous):

OpenStudy (anonymous):

180 - 115 = 65 and so the other two angles are each half of 180 - 65 = 115, so each is \[\frac{115}{2}\]

OpenStudy (anonymous):

ACD=180-115=25 degrees Let x= ADC 2 x + 25 = 180 (isosceles triangle) x = 155/2=77.5 degrees

OpenStudy (anonymous):

i think you have a math error there, 180-115 is not 25

OpenStudy (anonymous):

I think your are right. Haste makes waste.

OpenStudy (anonymous):

satellite73's solution is correct.

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