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What is the m∠ADC? A)57.5 B)65 C)90 D)115
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180 - 115 = 65 and so the other two angles are each half of 180 - 65 = 115, so each is \[\frac{115}{2}\]
ACD=180-115=25 degrees Let x= ADC 2 x + 25 = 180 (isosceles triangle) x = 155/2=77.5 degrees
i think you have a math error there, 180-115 is not 25
I think your are right. Haste makes waste.
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satellite73's solution is correct.
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