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simplify 49sqrt14 over 21sqrt3
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no no simplify
rationalize denominator and simplify
\[\frac{49\sqrt{14}}{21\sqrt3}=\frac{49\sqrt{14}\cdot\sqrt{3}}{21\sqrt3\cdot{3}}=\frac{49\sqrt{42}}{62}\]
sorry missed square in denominator should be \[21\sqrt3\cdot\sqrt3\]
hold on let me put in equation
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\[49\sqrt{14} \over 21\sqrt{3}\]
7sqrt14 -------- 3sqrt3
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