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how do we factor "18u^2-3u=1
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This is an equation so you can only find the solution.
Anyway for the LHS of the equation: 3u(6u - 1)
(3x-1)(6x+1)
all you do is subtract the one from both sides then you can factor it like any other equation
ok.
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thnxx 4 helping me :)
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