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y^2-8y+16=25
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9,-1?
y^2 - 8y + 16 = 25 move the 25 to the other side so it = 0
i can work it out so far lol but im catching on
\[(x=4)^2=25\] \[x-4=5\] \[x=9\] \[x-4=-5\] \[x=-1\] yup
y^2 - 8y + 16 - 25 = 0 y^2 - 8y - 9 = 0 a = 1 b = -8 c = -9 use the formula i stated before to work it out :) and the answer you have given is correct
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or if you prefer \[x^2-8x-9=0\] \[(x+1)(x-9)=0\] \[x=-1,9\]
lol i did and it worked out. thanks yall!
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