In a certain rectangle, the length exceeds the width by 2m. If the length is increased by 4m and the width is decreased by 2m, the area of the new rectangle is the same as that of the original rectangle. Find the dimensions of the original rectangle. What is the width and what is the length?

Question

lilg132 · Answer

original dimensions

width = x

length = x + 2

new dimensions

width = x - 2

l = x + 6

x(x + 2) = (x - 2) (x + 6)

x^2 + 2x = x^2 + 6x - 2x - 12

x^2 + 2x = x^2 + 4x - 12

-2x = -12

x = 6

lilg132 · Answer

original width = 6m
original length = 8m

new width = 4
new length = 12

lilg132 · Answer

width * length = 48m

lilg132 · Answer

dont forget to click good answer :)

anonymous · Answer

Thank you!!!

lilg132 · Answer

your welcome :)