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dividing radicals: what's 12/2-√15 is it 2√15/5 or am i wrong? I don't understand wolfram alpha
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it is telling you if you rationalize the denominator you will get \[-\frac{24+12\sqrt{15}}{11}\][
easier just to do it. write \[\frac{12}{2-\sqrt{15}}\times \frac{2+\sqrt{15}}{2+\sqrt{15}}=\frac{12(2+\sqrt{15})}{-11}\]
oh i see where i went wrong thanks!
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