Ask your own question, for FREE!
Physics 19 Online
OpenStudy (anonymous):

(4/x-1) + (5)/[(x+1)(x-1)] **** Would i be able to cross out the (x-1) in the denomerator?******

OpenStudy (anonymous):

no

OpenStudy (fretje):

(x+1)(x-1) equals x²-1 so you get (4/x-1) + (5)/(x²-1)

OpenStudy (fretje):

that looks cleaner, but it is not simpler

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!