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I need help with he following: Use the given values (if possible) the remaining trig fxns. tan x= 7/24 , sec x= -25/24
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us the given values to evaluate*
use*
tan^-1(7/24) sec^-1(-25/24)
I dont understand how you got that though.
ok. we can find the hypotenuse from tan x:\[c^2=a^2+b^2=7^2+24^2=625\]So, c=25. Now just do the usual:\[\sin x=\frac{7}{25}\]...etc
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This is about using identities though, i dont see how finding the hypotenuse relates with the such.
|dw:1322031506414:dw|
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