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radical equations help how do you solve √(x + 8) = √(3x+8)
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Square both sides
$$x+8=3x+8 \Rightarrow x=0$$
x+8 =3x +8 x-3x=8-8 -2x=0 x=0
is it like a regular algebra problem where you're solving for x after you get rid of the radical?
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