Question

What is the parabolic trajectory of a projectile shot from the origin of plane surface with an inclination angle of 55° and gets M = 41.94 m high, plus a parameter of P = 20.56 m?

Answer 1

Trayectoria del proyectil - Projectile trajectory
Proyectil - Projectile

Answer 2

from maximum height
\[t _{m}=\left( v _{0}\sin \Theta \over g \right)\]
we get
v0 = 502,265 m/s

the trajectory is

\[y=\tan \Theta- \left( g \over 2.v _{0}^{2}\cos ^{2}\Theta \right).x²\]

Answer 3

Thank you