Simplify [(3√5)^(9s+6)]/25.

The three should be little (above the square root of 5 in front.)

Question

Simplify [(3√5)^(9s+6)]/25.

The three should be little (above the square root of 5 in front.)

jhonyy9 · Answer

- so what is 3 ?

jhonyy9 · Answer

- so or you want saying that 3 wann to be the indice of radical than you wan talking from cuberoote of 5

jhonyy9 · Answer

than yes so there is 5 on exponent (1/3)(9s+6) this all divided by 5 on exponent 2
- so with exponent of 5 from numerator we can simplify by 3 and will get 5 on exponent 
(3s+2)
- than there will be 5 on exponent (3s+2) divided by 5 on exponent 2 
- than this is equal 5 on exponent ((3s+2)-5) what is equal (3s-3)=3(s-1) 
 so what is equal (125) on exponent (s-1)