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Simplify [(3√5)^(9s+6)]/25. The three should be little (above the square root of 5 in front.)
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- so what is 3 ?
- so or you want saying that 3 wann to be the indice of radical than you wan talking from cuberoote of 5
than yes so there is 5 on exponent (1/3)(9s+6) this all divided by 5 on exponent 2 - so with exponent of 5 from numerator we can simplify by 3 and will get 5 on exponent (3s+2) - than there will be 5 on exponent (3s+2) divided by 5 on exponent 2 - than this is equal 5 on exponent ((3s+2)-5) what is equal (3s-3)=3(s-1) so what is equal (125) on exponent (s-1)
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