simplify:a^3 b^2/5a^4b^7*2a^6b^/a^9b^3
you have made mistake 6^/
its a^6 b
\[\frac{\frac{a^3b^2}{5a^4b^7*2a^6b}}{a^9b^3}?\]
no
that looks correct to what he has said?
\[\frac{a^3b^2}{5a^4b^7*2a^6b}*\frac{1}{a^9b^3}\]
\[\frac{a^3b^2}{5a^4b^7}\cdot\frac{2a^6b}{a^9b^3}=\frac{1}{5a^4b^7}\]
that is correct for if it is 2 fractions
sorry missed 2 (WHERES EDIT BUTTON), answer is \[\frac{2}{5a^4b^7}\]
he placed only 1 asterisk (not after every a*b*a*b*...) so we can assume it's 2 fractions
Hey ocuane, next time you do such a problem, it'd be helpful to use the Equation Editor button below the text box.
yes tomas but it can be written such as what i put above. It doesn't necessarily need * every single time
he'd need to put it in parenthesis
\[5*a*b*6*a*b=5ab*6ab\]
i know that it can be interpreted various ways
that is hard to read
i think tomas does have the right interpretation
but i could be wrong
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