Question

(1,19),(2,4); y=a(x+1)^2+k
determine a and k so the given points are on the graph of the function

Answer 1

plug in two point in x, y to find a and k

Answer 2

19=a(1+1)^2+k
4=a(2+1)^2+k

Answer 3

replace x by 1 set result equal 19, get an equation in a and k
replace x by 2 set result equal 4, get another equation in a and k. solve the system of equations

Answer 4

what moneybird said

Answer 5

\[4a+k=19\]
\[9a+k=4\]
\[-5a=15\]
\[a=-3\] etc

Answer 6

19 = 4a + k
4 = 9a + k

4 = 9a + k
- 19 = 4a + k
------------
-15 = 5a
a = -3

k = 31