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Suppose ΔCED ≅ ΔDBC. If m∠EDC = 630 and m∠DBC = 820, what is m∠DCE? A.63 degrees B.82 degrees C.145 degrees D.35 degrees
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I assume they are 63 degrees and 82 degrees.
Look at the picture and you will notice that angle DBC is same as angle DEC = 82 degrees. You now have two angles of the triangle. Calculate the third one.
180m = 630 + 820 + m∠DCE 180m - m∠DCE = 1450
Thank you
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