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find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function.. f(x)=-x^2+8x+6
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x = 4 is the symmetry (4,22) is the vertex 22 is the maximum
use \[x=-\frac{b}{2a}\] to find a) the first coordinate of the vertex b) the axis of symmetry then replace x by this to find y, and that will give you the maximum
cant believe i got that right lol
oh the equation is x=4 right?
yup
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thanks. i got 2 more of these dang equations to do. thanks for your help.
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