Question

let f(x)=x^3-4. find f(a+3)

Answer 1

whre you see 'x' , change it with 'a+3'

Answer 2

\[f(a+3)=(a+3)^3-4\]

Answer 3

\[f(\spadesuit)=(\spadesuit)^3-4\]
\[f(x)=(x)^3-4\]
\[f(\Box)=(\Box)^2-4\]
\[f(a+3)=(a+3)^2-4\]
etc.

Answer 4

incorrect with square :P

Answer 5

Oh poo. Did I square it instead of cube it? :( The darn font is so tiny.

Answer 6

next time instead of square use cube :D

Answer 7

I'll just set my zoom trigger to 200%. (Right click math symbols, settings, zoom trigger..) ;-p

Answer 8

but with zoom factor you will see it only when question is posted, not while editing or not?

Answer 9

Please help! classify this conic equations:
1) \[x ^{2}+y ^{2}+2x+2y+1=0\]
2) \[2x^{2}+2y^{2}-4x+4y+19=0\]
3) \[x^{2}+4y^{2}=100\]
4) \[8x ^{2}+3y ^{2}=120\]
5) \[y=x^{2}-2x+3\]

Answer 10

so is that the final answer or can i simplify that?

Answer 11

you can

Answer 12

that is
f(a + 3)= (a + 3)^{3} - 4
= a^3 +3a^2 + 9a + 27 - 4
= a^3 + 3a^2 + 9a + 23

Answer 13

oh ok iwow this is tough lol