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simplify by removing factors of 1 3p^2+39/21p^2+9p
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Factor out the 3 in the numerator and then factor out 3p in the denominator. Remember: always look for a common factor first.
Try it then I will show you.
it would be 3 21 9 right
was i right
For the numerator it would be 3(p^2+13) For the denominator it would be 3p(7p+3)
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Now the 3 is common in the top and bottom so it can be cancelled out and replaced with 1. So the final answer is:\[\frac{p ^{2}+13}{p(7p+3)}\]
where did you get 7 from
21p2 =3p * 7p
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