Question

I need help

Answer 1

(x^2-16)(x+1)^2\[\le\]0

Answer 2

so what do you need done?

Answer 3

i need to graph the solution set

Answer 4

ooo. try googling "graphing inequalities"

i dont remember how to do these exactly :p

Answer 5

ok thanks for the suggestion

Answer 6

np

Answer 7

(x^2-16)(x+1)^2≤0
(x-4)(x+4)(x+1)^2≤0

(x+1)^2 is always Positive.

Condition 1
x-4 ≥0 and x+4≤0
--> No answer for x (A)

Condition 2
x-4≤0 and x+4 ≥0
--> -4≤x≤4 (B)

Form (A) and (B)
-4 ≤ x ≤4