Question

if log3(4 approx. 1.2619),evaluate log3 (.25)
PLEASE HELP!!

Answer 1

Does it help to know that
\[ 4^{-1} = 0.25 \]

Answer 2

i dont know how to do this :/

Answer 3

and
\[ log(a^{b})= b \cdot log(a) \]

Answer 4

what do u do though?

Answer 5

in your second equation
\[ log_3(0.25) \approx 1.2619 \]
replace 0.25 with \( 4^{-1} \)
then look at the second "rule" I posted and see if it matches

Answer 6

i get it now thank you