Question

I am needing help if someone can explain how to find the solution set for (x^2-6x)^2-35(x^2-6x)-200=0

Answer 1

solve
\[z^2-35z-200=0\] the replace z by
\[x^2-6x\] and solve those

Answer 2

solutions to first one is ok because it factors as
\[(z-40)(z+5)=0\]
\[z=40,z=-5\] then solve
\[x^2-6x=40\] and
\[x^2-6x=5\] to finish up

Answer 3

So as I what was mentioned above I get x=10, -4, 5, 1????