Question

Parabolas of the form y=-1/4x^2+x+C are shown.What is the value of C for which the equation -1/4x^2+x+C=0 has no real solution. With the given numbers...

-7
-1
0
3
5

Answer 1

compute
\[b^2-4ac\] and then make sure
\[b^2-4ac<0\]

Answer 2

\[1-4(-\frac{1}{4})C<0\]
\[1+C<0\]
\[C<-1\]

Answer 3

sorry should be
\[C\leq -1\] so -1 would give a real solution but -7 would not