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Chemistry 9 Online
OpenStudy (anonymous):

calculate the volumes of the following gases at the conditions stated : 3.00 moles of co2 at 202.6 kPq and 273 degrees cel

OpenStudy (matt101):

273C = 546K Also I'm assuming you meant 202.6 kPa PV=nRT (202.6)V = (3)(8.314)(546) --> V = 67.22 L

OpenStudy (anonymous):

YEAH ! i meant kPa (: oh.. hehe. okay thanks xD

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