Question

Two years ago a father was four times as old as his son three years from now he will be only three times as old as his son how old is each now?

Answer 1

Let present age of father be F and present age of son be S.
As per the problem,
(F-2) = 4*(S-2) and
(F+3) = 3*(S+3)

Solving for F and S,
F = 42
S = 12