Question

Two years ago a father was four times as old as his son three years from now he will be only three times as old as his son how old is each now?

Answer 1

(f-2) = 4(s-2)--------------1
f+3 = 3(s+3)--------------2

Answer 2

x father's age now
y son's age now
\[\begin{cases}(x-2)=4(y-2)\\(x+3)=3(y+3)\end{cases}\]

Answer 3

1) f = 4s-8+2 = 4s-6
2) f = 3s+9 - 3 = 3s + 6
so, 3s+6 = 4s - 6
s=12
f = 42

Answer 4

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Answer 5

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