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help simplify- with work shown please :) (5i)(3-2i)
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*remember \[i^2= -1\] and when you distribute, you get \[15i - 10i^2\] so...?
im still lost :(
Do you know that \[i = \sqrt{-1}\]
yes
is the first step to dist. 5i to 3-2i ?
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? so \[i^2 = -1\] If you distribute the 5i to the numbers inside the ( )
Yes
from 15i-10i^2 i dont know what to do! :(
(5i)(3-2i) =(5i)*(3-2i) =5i*3+5i*(-2i) =15i-10i^2 =15i-10*(-1) <-- i^2=-1 =15i+10
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