Question

PLEASE HELP!

Multiply Algebraic Fractions

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Answer 1

multiply straight across:\[{2x^2-50\over2x-10}\times{4x-2\over6x+30}={(2x^2-50)(4x-2)\over(2x-10)(6x+30)}\]factor a 2 out of everything except the term in the bottom-right where we factor out a 6\[ 6x+30=6(x+5)\]and we now have\[{(x^2-25)(2x-1)\over3(x^2-25)}\]multiply out the top and simplify; you should have your answer.

Answer 2

would it be