Question

the product of two numbers is 88. algebraically determine the number if onenumber is 3 is more than the other

Answer 1

Say the two numbers are x and y. That means xy=88. If y is three more than x, then y=x+3. That means x(x+3)=88.

x(x+3)=88
x^2 + 3x = 88
x^2 + 3x - 88 = 0
(x-8)(x+11)=0
x = 8, -11

Therefore the numbers could be 8 and 11 or -11 and -8. Either way, one is 3 more than the other.