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OpenStudy (anonymous):
Graph the integrals and use geometric formulas to evaluate the areas. (Do not integrate) *p.s. I will put the integral using equation editor in my reply section
14 years ago
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OpenStudy (anonymous):
\[ \int\limits_{-6}^{3} (1/3x + 3) dx\] A=h/2 (b1 +b2)
14 years ago
OpenStudy (anonymous):
what is this?
14 years ago
OpenStudy (anonymous):
my professor wanted me to graph this integral, and find the area
14 years ago
OpenStudy (anonymous):
whoa, did u just do that?
14 years ago
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OpenStudy (anonymous):
wolfie did it
14 years ago
OpenStudy (anonymous):
uhh okay, but how did u know how to do it?
14 years ago
OpenStudy (anonymous):
you have to
14 years ago
OpenStudy (anonymous):
i'm just asking cuz i have an exam this thursday, and i would have to know how to do this by hand, which i don't :(
14 years ago
OpenStudy (anonymous):
plot y=1/3x +3
do it using Draw button
14 years ago
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OpenStudy (anonymous):
is it possible to do this manually?
14 years ago
OpenStudy (anonymous):
graph y=1/3 x +3
start at (0,3) go up by 1 , right by 3
14 years ago
OpenStudy (anonymous):
makes sense so far...
14 years ago
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