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OpenStudy (anonymous):
Struggling with this anti derviative. It is (2e^x)-3e^-2x I get that the first one is (2e^x)+c but what is the antideriative of 3e^-2x?
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OpenStudy (zarkon):
antiderivative of \[ae^{bx}\] is \[\frac{ae^{bx}}{b}+c\]
OpenStudy (zarkon):
ok?
OpenStudy (anonymous):
Okay I think. But when I get one +C and another +C is it still just +C?
OpenStudy (zarkon):
yes...you can combine all the constants into one
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