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Mathematics 7 Online
OpenStudy (anonymous):

Struggling with this anti derviative. It is (2e^x)-3e^-2x I get that the first one is (2e^x)+c but what is the antideriative of 3e^-2x?

OpenStudy (zarkon):

antiderivative of \[ae^{bx}\] is \[\frac{ae^{bx}}{b}+c\]

OpenStudy (zarkon):

ok?

OpenStudy (anonymous):

Okay I think. But when I get one +C and another +C is it still just +C?

OpenStudy (zarkon):

yes...you can combine all the constants into one

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