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Mathematics
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Factor: 9x^3-x
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Take x out. You get x(9x^3-1).
This is the entire problem, I'm supposed to write it in the lowest terms. \[6x^{2}-13x-5/9x^3-x\] I've done the top but now I can't get the bottom right.
It is x*(9x^2-1) = x(3x+1)(3x-1)
oh yeah! the difference of two squares. okay. oh thank you! :D
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