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3x=sqrt1+8x solve
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\[3x=\sqrt{1+8x}\]
all i can see is x=1 is the solution o.O as 3= sqrt of 9
I'll try that o.O thanks XD
9x^2-8x-1=0 9x^2-9x+x-1=0 9x(x-1)+1(x-1)=0 (x-1)(9x+1)=0 x=1 or x=-1/9 but x cant be negative so x=1
hope that helps :D
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umm you get it?
Yes :D thanks so so so much!!!!! *hug*
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