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OpenStudy (chely2013):
how do i find the derivative of the natural log of x squared? [ln(x^2)]
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OpenStudy (anonymous):
d/dx(lnx2) = d/dx2(lnx2) . dx2/dx = 1/x2 . 2x = 2/x
OpenStudy (anonymous):
you got to use chain rule
OpenStudy (anonymous):
or simply power/x i.e 2/x
OpenStudy (chely2013):
thank you so much!
OpenStudy (anonymous):
welcome very much
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