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In the following figure, squares ABVY and ABUW formed the rectangle WYVU and the perimeter of the equilateral triangle YZV is 48. Which is the area of the rectangle?
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512. the length of a side of one of the squares would be 16, the same as the length of the side of the triangle. Therefore, the squares would have area 256 each. Multiply 256 by 2 to get 512.
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