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how do you find n in this type of equation: 81=3 to the power of n-1? Obviously here n is 5, but is there some formula for figuring that out?
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81 = 3^4 4 = n-1 n = 5
yeah, i get that, but assuming that the #s aren't 81 and 3, and you don't already know what the exponent should be. How would you figure it out?
You can use logarithum log 81 / log 3 = n-1
thanks
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