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find the value of theta
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7x10^90
\[\cot^2\theta-\tan^2\theta=0\]
what is the value of \[\theta\]
2.) \[2\sin^2\theta+\cos \theta+1=0\]
This would be equivalent to saying that the cot^2 = tan^2 or that cot = tan or that cos/sin=sin/cos or that sin^2 = cos^2. The only way that could be true is if the side opposite = the side adjacent. This then would be a 45-45-90 triangle.
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how can I find the value of the angle?
help please
Well, in a 45-45-90 triangle, the angle would be 45
|dw:1322620099338:dw|\[f\]\[\cot ^{2}\Theta-\tan ^{2}\Theta = 0\]
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