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Mathematics 20 Online
OpenStudy (moongazer):

find the value of theta

OpenStudy (mertsj):

7x10^90

OpenStudy (moongazer):

\[\cot^2\theta-\tan^2\theta=0\]

OpenStudy (moongazer):

what is the value of \[\theta\]

OpenStudy (moongazer):

2.) \[2\sin^2\theta+\cos \theta+1=0\]

OpenStudy (mertsj):

This would be equivalent to saying that the cot^2 = tan^2 or that cot = tan or that cos/sin=sin/cos or that sin^2 = cos^2. The only way that could be true is if the side opposite = the side adjacent. This then would be a 45-45-90 triangle.

OpenStudy (moongazer):

how can I find the value of the angle?

OpenStudy (moongazer):

help please

OpenStudy (mertsj):

Well, in a 45-45-90 triangle, the angle would be 45

OpenStudy (mertsj):

|dw:1322620099338:dw|\[f\]\[\cot ^{2}\Theta-\tan ^{2}\Theta = 0\]

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