Question

Write the quadratic function in vertex form. Then identify the vertex. y=x^2+20x+90…please explain

Answer 1

find the vertex via
\[x=-\frac{b}{2a}\] in this case you get
\[-\frac{20}{2}=-10\] for the first coordinate. replace x by -10 to find the second coordinate of the vertex

Answer 2

y=(x+10)^2-10

so V(-10;-10)

Answer 3

sat, can u please come back to my question?

Answer 4

thanks

Answer 5

you will find that y = -10 as well, so you get what ghass said
\[y=(x+10)^2-10\]