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Solve the trigonometric equation 3tan^2 2theta - 1 = 0
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Interval [0, pi]
theta=x 3tan^2 (2x) = 1 tan^2(2x) = 1/3 tan(2x) = 1/rt(3)........rt=root under tan(2x) = tan 30 2x = 30 x= 15
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