Question

-16x^2+9y^2-160x+12y-400=0 need to graph

Answer 1

Find the tables of values with values of x and corresponding values of y for example when x=1 , y=something,.......and plot in graph......

Answer 2

complete da square

Answer 3

-16(x^2+10x) + 9( y^2 + 4/3 y ) = 400

Answer 4

-16(x^2 + 10x + 25 - 25) + 9(y^2 +4/3y + 16/36 - 16/36) = 400

Answer 5

-16(x+5)^2 + 25*16 + 9(y+2/3)^2 - 9*16/36 = 400

Answer 6

-16(x+5)^2 + 9(y+2/3)^2 = 400 - 25*16 + 9*16/36 = 4

Answer 7

(x+5)^2/(1/2)^2 + (y+2/3)^2 / (2/3)^2 = 1

Answer 8

an ellipse centered at (-5, -2/3) with a width of 1/2 and a height of 2/3

Answer 9

missed a sign in that last step, it's
-(x+5)^2/(1/2)^2 + (y+2/3)^2 / (2/3)^2 = 1

Answer 10

a hyperbola