Question

Part a.) Write the equation of the line that has a slope of -2 and a y-intercept of -6. (5 points)

Part b.) Write the equation of the line that passes through the point (6, -2) and has a slope of -2/3. (5 points)

Answer 1

y=mx+c
where m is the slope and c is the y intercept

Answer 2

a) y=kx+m where k=slope and, m=y-intercept

--> y=-2x-6

Answer 3

b) same principle... y=kx+m -->
-2=-2/3*6+m

m=2

--- > y=-2/3x+2

Hope this helps...

/Ali