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x^2-5x+5=0 what are the solutions to approx 3 decimal places
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use quadratic formula
do you know the quadratic formula
this is what ive gotten so far x-8= \[-\sqrt{20}\]
\[x-8=-\sqrt{20}\]
using the formula ? remember a = 1 b = -5 c = 5
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This one seems to only have one solution. Apply the following formula:\[\frac{-b \pm \sqrt{b^2 - 4 a c}}{2a}\]where a, b, and c correspond to the coefficients of your quadratic equation \[ax^2 + bx + c = 0\]
and because b = -5 and it says to input -b in the formula just remember - * - = + so where it says -b you should put 5 not -5
thats whats throwing me off is the abc formula
what is
when i have to put it into the different formula
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