Question

log(down)4 (x^2-3x)=1

Answer 1

\[\log_{4} (x ^{2}-3x)=1\]

Answer 2

\[\log_{4}(x^{2}-3x)=1\]


\[x^{2}-3x=4^1\]


\[x^{2}-3x=4\]


\[x^{2}-3x-4=0\]


\[(x-4)(x+1)=0\]


\[x-4=0 \ \text{or} \ x+1=0\]


\[x=4 \ \text{or} \ x=-1\]

Answer 3

THank you!!

Answer 4

yw