Let f(t) be a function defined on [-1,7]. For -1≤t≤0 the graph of f(t) is the upper right quarter of a circle of radius 1 centered at (-1,0); For 0<t<2 the graph of f(t) is the bottom half of a circle of radius 1 centered at (1,0);For 2≤t<4 the graph of f(t) is a straight line with left endpoint (2,1) and slope 3/2; Finally on the interval [4,7], f(t) is continuous but its graph is an unknown curve. Furthermore it is known that the "integral of f(t)dt from 3 to 5 =4" and "integral of f(t)dt from 5 to 7 =5". compute the "integral f 8f(t)+1dt drom 2 to -1"?

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Calculus1 22 Online

OpenStudy (anonymous):

Let f(t) be a function defined on [-1,7]. For -1≤t≤0 the graph of f(t) is the upper right quarter of a circle of radius 1 centered at (-1,0); For 0 14 years ago

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