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OpenStudy (anonymous):
evaluate the integral by interpreting it it terms of areas. [0,9] (1/3x-2)
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OpenStudy (jamesj):
Draw a graph of the the straight line y = x/3 - 2. Notice that it makes with the x-axis two triangles. Find the area of those triangles. One of the triangles which is below the x-axis has negative area. The integral is then the sum of the area of the two triangles, one negative, the other positive.
OpenStudy (anonymous):
thank you!
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