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–x + 3y = 9 than please describe how to graph using slope intercept form
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When x intercept put x = 0 when y intercept put y = 0
nd then?
try solving..
for?
y=x/3+3
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When x intercept put x = 0 -x + 3y = 9 -x + 3(0) = 9 solve. when y intercept put y = 0 This one as well.
noo... thats not what its asking.. thanks anyway!
that's the thing how u are going to graph it.
–x + 3y = 9 in slope intercept form is \[y = \frac{9+x}{3}\]
where the slope is 1/3 and the intercept is 3
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this is waht i got... y=mx+b 3y=x+9 y=x/3+3
\[y = \frac93 + \frac x3\] \[y = \frac x3+3\]
lol, why'd it take you so long saifoo?
hero click on waht i just posted
i was in another tab. :p
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