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i need help graphing a quadratic function
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Sure. do u have a problem?
how do you graph x^2+6x+5 how do i find the slope
quadratic equation isnt constant. so it's slope changes..
how do u figure out the slope
u dont have to find it's slope. for sketching the quadratic equation u have to find the vertex and the y-intercept that's it.
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should i do it for u?
please show me an example
x^2+6x+5 =0 x^2 + 6x +(3)^2 - (3)^2 + 5 = 0 (x+3)^2 -9 + 5 = 0 (x+3)^2 - 4 = 0 So, vertex = (-3, -4) ===================================== now find the y intercept x^2+6x+5 =0 (0)^2+6(0)+5 =0 5 so, (0,5)
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