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Mathematics 19 Online
OpenStudy (curry):

((x+1)(2x+1)^2)/((x^2-1)(x-3))

OpenStudy (anonymous):

x^2-1 can be written as (x-1)(x+1). So, you get simplify from there.

OpenStudy (curry):

find zeros asymptotes holes end behavior , vertical asymptote behavior

OpenStudy (curry):

and multiliplicity

OpenStudy (anonymous):

A complete analysis of the expression, ((x+1)(2x+1)^2)/((x^2-1)(x-3)), using Mathematica 8.04 Home Edition is attached.

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