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OpenStudy (anonymous):
Does anyone know how to solve a system by substitution????
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hero (hero):
Yup
OpenStudy (anonymous):
can you help me
hero (hero):
This is a pre-question. It would be easier for you to just post the actual equations that need "subbing"
OpenStudy (anonymous):
its this one
{2x+3y=0
{x+2y=-1
OpenStudy (lilg132):
rearrange one of the formulas to get the answer for one variable
and use this on the other equation to with that variable
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OpenStudy (anonymous):
yes but i need the steps
OpenStudy (anonymous):
can you show me???
OpenStudy (lilg132):
e.g.
x = -1 -2y
2(-1 -2y) + 3y = 0
-2 -4y + 3y = 0
-4y + 3y = 2
-y = 2
y = -2
OpenStudy (lilg132):
dont forget to click good answer
OpenStudy (anonymous):
what about the X
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OpenStudy (lilg132):
ok so now we know the value of y we use it to work out x
so we know y = -2
x + 2(-2) = -1
x - 4 = -1
x = 4 -1
x = 3
OpenStudy (lilg132):
to check use both variables on the other equation
so
x = 3 and y = -2
2(3) + 3(-2) = 0
6 - 6 = 0
OpenStudy (lilg132):
dont forget to click good answer :)
OpenStudy (anonymous):
thank you can you help me on two more ??
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