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(x-8)^2=20 give exact solutions and to three decimal places
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first foil the left hand side
then subtract 20 from both sides so you get a quadratic equal to zero. then use the quad formula to solve for x.
(x-4)(x+4)?
no. (x-8)^2 = (x-8)(x-8) now foil
x^2-8x-8x-64 x^2-64
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combine the -8x and -8x to get -16x, and (-8)*(-8) = +64, so after foiling you should get x^2 -16x +64
oh dang so I add instead of subtract them?
yes, because they are both negative.
ok so how do i get my solutions?
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