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Rewrite the sum 1/2-1/4+1/8-1/16+1/32-1/64+1/128 using sigma notation
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start with \[\sum_{k=1}^7\frac{1}{2^k}\] and then make it alternate sign
gimmick there is to write \[(-1)^k\] or \[(-1)^{k+1}\] depending on which terms are positive and which are negative in this case you will want \[\sum_{k=1}^7\frac{(-1)^{k+1}}{2^k}\]
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